converting image in a clipboard to memory stream

converting image in a clipboard to memory stream

• Menghraj

  Are you sure you have something on the clipboard of type Bitmap
  
  1. I opened mspaint.exe
  2. Drew something on the canvas
  3. Made a selection
  4. Copied the selection
  
  Ran the exact same code and it works for me.
  
  Also, you might want to move the line
  
  Image imgClipboard = (Image)iDataObj.GetData(DataFormats.Bitmap);
  
  into the "if" block.
  
  

• bebop

  An unhandled exception of type 'System.ArgumentNullException' occurred in system.drawing.dll
  
  Additional information: Value cannot be null.
  
  showed up when i did this.
  private void contextMenuPasteImage_Click(object sender, System.EventArgs e)
  {
  IDataObject iDataObj=Clipboard.GetDataObject();
  //determine the format of data
  if (iDataObj.GetDataPresent(DataFormats.Bitmap))
  {
  Image imgClipboard = (Image)iDataObj.GetData(DataFormats.Bitmap); //imgClipboard.Save(ms,System.Drawing.Imaging.ImageFormat.Jpeg); pictureBox1.Image=(Image)iDataObj.GetData(DataFormats.Bitmap); pictureBox1.Image.Save(ms,pictureBox1.Image.RawFormat);
  arrImage = ms.ToArray(); //this LINE generates the NULL REF exception byte[]==arrImage
  ms.Close();
  
  }
  
  
  }
  is there a problem wit image formats
  
  

• Diamond.Yu

  nope that didnt work.
  the problem is when i create an image object from the clipboard. i get nothing.
  private void contextMenuPasteImage_Click(object sender, System.EventArgs e)
  {
  IDataObject iDataObj=Clipboard.GetDataObject();
  Image imgClipboard = (Image)iDataObj.GetData(DataFormats.Bitmap);
  //determine the format of data
  if (iDataObj.GetDataPresent(DataFormats.Bitmap))
  {
  
  
  pictureBox1.Image=imgClipboard;
  
  }
  
  picturebox is still empty when is paste the picture
  
  

• MDXXI

  //contxmenu event haandler for pasting the picture
  private void contextMenuPasteImage_Click(object sender, System.EventArgs e)
  {
  
  IDataObject iDataObj=Clipboard.GetDataObject();
  Bitmap imgClipboard;
  //determine the format of data
  if (iDataObj.GetDataPresent(DataFormats.Bitmap))
  {
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp );
  arrImage=(Byte[])ms.GetBuffer();
  ms.Close();
  //p/asteStat=true;
  }
  
  else
  {
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp);
  arrImage=(Byte[])ms.GetBuffer();
  ms.Close();
  
  }
  
  //to determine appropriate format
  
  
  
  
  // the actual code that insert the record ito the database
  private void btnInsertItems_Click(object sender, System.EventArgs e)
  {
  //ms=new MemoryStream();
  //save picture to memory stream
  /*
  if (pictureBox1.Image!=null && pasteStat==false)
  {
  pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
  arrImage = ms.GetBuffer();
  ms.Close();
  }
  */
  //connection object
  string sqlInsertMenu="INSERT INTO Menu (Item_Name,Description,UnitPrice,Type,Image)"+
  "VALUES (@Item_Name,@Description,@UnitPrice,@Type,@Image)";
  SqlConnection conn=new SqlConnection(connString);
  SqlCommand cmd=new SqlCommand(sqlInsertMenu,conn);
  //add paramters to the command object
  try
  {
  
  cmd.Parameters.Add(new SqlParameter("@Item_Name",SqlDbType.Char,35)).Value=Convert.ToString(txtInput1.Text);
  cmd.Parameters.Add(new SqlParameter("@Description",SqlDbType.Char,50)).Value=Convert.ToString(txtInput2.Text);
  cmd.Parameters.Add(new SqlParameter("@UnitPrice",SqlDbType.Money,8)).Value=Convert.ToInt32(txtInput3.Text);
  cmd.Parameters.Add(new SqlParameter("@Type",SqlDbType.Char,35)).Value=Convert.ToString(txtInput4.Text);
  cmd.Parameters.Add(new SqlParameter("@Image",SqlDbType.Image)).Value=arrImage;
  }
  
  catch (Exception ex)
  {
  //exception code
  MessageBox.Show(ex.Message);
  }
  //open the connection and insert the data
  try
  {
  conn.Open();
  cmd.ExecuteNonQuery();
  MessageBox.Show("One Records inserted");
  }
  catch(Exception ex)
  {
  MessageBox.Show("An Error occured: "+ex.Message);
  
  }
  finally
  {
  conn.Close();
  }
  
  
  
  
  
  
  }
  
  

• Duece

  MemoryStream.GetBuffer() will return the underlying buffer.  Use ToArray() to get just the interesting portion.
  
  Unless you haven't initialized "ms", I don't see any reason why ms.GetBuffer() should throw.
  
  If it were to do with image formats, I would expect the Image.Save method to throw.  However in my experiments, Image.Save has worked for pretty much all formats.
  
  Also, please explain what you mean by "insert the database"
  
  So far you've reported 3 different problems (ArgumentNullException, Picture box not showing picture and Null reference exception).  It'll be nice to know if you've actually solved the other 2 problems.
  
  Thanks
  

• RGD_DBA

  i was actually trying to update the database by pasting an image in the picturebox.
  the picture appears on the picturebox but when i insert the database. the code:
  arrImage=ms.GetBuffer();
  arrImage=byte[]
  ms=memorystream
  
  thrown a null excpetion.
  i saved the image to the memory stream using
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp); arrImage=(Byte[])ms.GetBuffer();
  ms.Close();
  
  the problem is visble in some image formats.
  please help
  
  

• Nagesh_techie

  Can you paste the code that inserts the image into your database
  

• Rahul Kumar

  i figured it ou. the problem was with the memory stream.
  the problem was created when saving multiple images to the clipboard and the memory stream was filled with multiple images.
  solution
  if there already exists image
  msImage.Position=0; //sets the pointer to the first location in the stream
  
  caution:
  donot close the memory stream
  i.e. remove ms.Close();
  becuase we need to paste images many times.
  here is the final code below. thanks for ur help guys.
  //clear the picturebox
  if (pictureBox1.Image!= null)
  {
  ms.Position=0;
  pictureBox1.Image.Dispose();
  pictureBox1.Image = null;
  }
  IDataObject iDataObj=Clipboard.GetDataObject();
  Bitmap imgClipboard;
  //determine the format of data
  try
  {
  if (iDataObj.GetDataPresent(DataFormats.Bitmap))
  {
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp);
  arrImage=ms.ToArray();
  }
  else
  {
  MessageBox.Show("The Clipboard does not contain an image");
  
  }
  
  

• Muthu Arumugam

  The following code is wrong.
  
  IDataObject iDataObj=Clipboard.GetDataObject();
  Bitmap imgClipboard;
  //determine the format of data
  if (iDataObj.GetDataPresent(DataFormats.Bitmap))
  {
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp );
  arrImage=(Byte[])ms.GetBuffer();
  ms.Close();
  //p/asteStat=true;
  }
  
  else
  {
  imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);
  pictureBox1.Image=imgClipboard;
  pictureBox1.Image.Save(ms,System.Drawing.Imaging.ImageFormat.Bmp);
  arrImage=(Byte[])ms.GetBuffer();
  ms.Close();
  
  }
  
  If the clipboard doesn't have an image, you're still doing a iDataObj.GetData with DataFormats.Bitmap.  This will return you a null object.  The else clause is wrong and should be replaced with an Error dialog or something.  Also, don't keep ms as a member, if you just want access to arrImage.  And, use ToArray() instead of GetBuffer().  Try the following:
  
  

  private void contextMenuPasteImage_Click(object sender, System.EventArgs e) {     IDataObject iDataObj=Clipboard.GetDataObject();     Bitmap imgClipboard;     if (iDataObj.GetDataPresent(DataFormats.Bitmap))      {          imgClipboard=(Bitmap)iDataObj.GetData(DataFormats.Bitmap);          pictureBox1.Image=imgClipboard;               MemoryStream msLocal = new MemoryStream();         pictureBox1.Image.Save(msLocal, System.Drawing.Imaging.ImageFormat.Bmp);         arrImage = msLocal.ToArray();          msLocal.Close();     }      else      {          MessageBox.Show("Nothing to paste!");     } }

  
  

• Shimit

  i did that by creating an image object instead of a bitmap object. let me see if that works.
  
  

• yaoyao

  You are almost there.  Here's the missing piece:
  
  

  IDataObject iDataObj = Clipboard.GetDataObject(); //determine the format of data if (iDataObj.GetDataPresent(DataFormats.Bitmap)) {     Image image = (Image)iDataObj.GetData(DataFormats.Bitmap);     System.IO.MemoryStream memStream = new System.IO.MemoryStream();     image.Save(memStream, System.Drawing.Imaging.ImageFormat.Jpeg);     byte[] buffer = memStream.ToArray(); }

  
  
  HTH
  
  

• leo2

  sorry eh for my language. ihave been trying to update the database with an image field
  it works pretty fine when i insert the images from a file, but i can't figure it out by pasting from the clipboard. as far as the memory stream: it is declare as
  private MemoryStream ms=new MemoryStream();
  in the class declaration.
  does it create a problem.
  kindly, please show me the code to insert image into database by pasting a picture in the picturebox. that would be veeeery helpful.
  ps:
  ieven tried ms.ToArray(), but i end up with the same results.
  
  

• Mitch Kupferman

  there was nothing new i'd already tried it.
  i figured it out why it didn't work.
  try pasting the image twice. then see what happens.
  finding a workaroung for this
  how to clear the memory stream
  will Flush() method work
  
  
  
  

• Action12

  Image.RawFormat will give you the format of the current image - I'm not sure if this is the intended usage of this property.
  
  Try one of the static members of the ImageFormat class: Bmp, Gif, Jpeg, Png, etc.

  
  
• converting image in a clipboard to memory stream