Cannot figure out how to write this script?

Cannot figure out how to write this script?

• Tonny.MS

  thanks a lot for your reply that worked!!!!!!!

  thanks again

  
  
  

• Nitin2162000

  You can then use just replace like:

  declare @s nvarchar(512), @p int
  set @s = N'Entrada ""{0}"" en ubicacion """"{1}"""""
  在或大 ""{0}"" 的命令出
  User Post Code Group of Type ""{0}"" is ""{1}""
  '
  print replace(replace(replace(@s, '""', '"'), '""', '"'), '""', '"')
  

  
  
  

• Geek cra451

  You don't need the loop since REPLACE will replace all occurrences of the specified string. And the WHERE clause of UPDATE gets the qualifying rows. Just a simple UPDATE will suffice.
  
  

• John Landreth

  Or you can do your update in a loop and additionally include required criteria

  SELECT top 1 * FROM LocalisationText
  
  WHILE @@ROWCOUNT > 0
  BEGIN

  UPDATE LocalisationText_Test
  SET ResourceText = REPLACE(ResourceText,'''''','''')
  WHERE ResourceText LIKE '%''''{[0-9]%'
  OR ResourceText LIKE '%[0-9]}''''%'

  END

  GO

  
  

• itx

  Is this a text/ntext column or varchar/nvarchar column Please take a look at PATINDEX function. You can use a pattern like '%""{[0-9]}""%' to locate the double-quotes you want to replace and then use updatetext for text/ntext or stuff for varchar/nvarchar. And you will need to perform this iteratively until you don't find any matches for the pattern. This will provide a replace with search based on a pattern behavior.
  
  

• Enkht

  Hi there

  thanks for your reply.

  The column in question is an nvarchar 512.

  I will look into patindex function .

  Do you have a quick example how I could do it

  thanks

  
  
  
• Cannot figure out how to write this script?