RegEx

RegEx

• aydinserkan

  Thank u,
  
  haven't tried it yet, but I guess it'll work.
  
  Bye,
  Finch.
  

• IsabellaTsoglin

  Ur pattern is always true, since it doesn't matter with what the string starts. But the problem is not the pattern, the problem is the syntax. I can an error, when I use "\\" and the pattern won't find the right string when I use "[\\]"...
  This one here works just as it should:
  
  "^[a-zA-Z_0-9]+.{1}[a-zA-Z_0-9]+[.]jpg$"
  
  I used a wildcard ".{1}" instead of "\\".
  But why do I get problems with the backslash "\w" instead of "[a-zA-Z_0-9]" didn't work either...
  Maybe u have to escape it by using a special method... don't know.
  
  Finch

  
  

• etiennemartin

  From what I've seen the RegEx syntax does not differ from what is used in perl , php etc...
  
  in the example you have given
  
  ^[a-z] -> match from the beginning of the string. This is the same in any language.
  [^a-z] -> means does not contain a character
  
  You can use the RegEx workbench here to test your regex http://www.gotdotnet.com/Community/UserSamples/Details.aspx SampleGuid=C712F2DF-B026-4D58-8961-4EE2729D7322
  
  
  The RegEx reference I use is from here http://gmckinney.info/resources/regex.pdf
  
  Hope this helps...
  
  

• NatashaKarlsson

  I got your problem now .. I missed it earlier
  should have got it earlier
  Thing is when you give the regex pattern as a string, you have to escape it. yes you are escaping it in the regex, but the pattern itself is a string, so you have to escape it again.
  Like if you have the \\ in your pattern, you have to escape each \ again like \\\\
  so the pattern [\w]+\\[\w]+[.]jpg$ should be written as
  
  [\\w]+\\\\[\\w]+[.]jpg$
  
  but the simplest way is to tell the compiler to treat your pattern as a literal like
  
  Regex = new Regex(@"[\w]+\\[\w]+[.]jpg$");
  so then you dont have to escape it again. Thats a new rule of thumb :)
  
  
  
  

• Evan Winslow

  [a-zA-Z_0-9]+\\[a-zA-Z_0-9]+[.]jpg$
  
  I matched it from the end of the string
  so you will get the filename and the folder
  
  

• JDevitt

  Thanks for ur reply,
  
  Great links!
  But:
  I want to strip certain parts of a path-address.
  I need "\folder\file.jpg" out of "c:\root\directory\folder\file.jpg"
  My RegEx for this is:
  ^[\\][a-zA-Z_0-9]+[\\][a-zA-Z_0-9]+[.]jpg
  I tried [\w] doesn't work. (Very wired).
  Well, this RegEx returns "file.jpg". I think it's because of the [\\]...
  I used the RegEx Workbench and the result was what I wanted..
  
  Can anybodey help me
  Here is the exact code:
  
  

  public string FormatFilename(string s)

  {

     Regex reg = new Regex("\[a-zA-Z_0-9]+[.]jpg");
     while (!reg.IsMatch(s))
     {

        s = s.Remove(0,1);

     }

        return s;

     }//FormatFilename

  
  
• RegEx