The wrong name space was used for XSL headaches...

The wrong name space was used for XSL headaches...

• jbatty

  Jim,

  You are missing <xsl:stylesheet ... at your stylesheet. (the xsl: prefix)

  Thanks,

  Sinan

  
  
  

• Ryan_H

  Thanks for the help. When it comes to XML and XSLT I am a newbie. Isn't it obvious

  Basically, what I'm trying to do is, use the XML server control to display information in a XML document. The only record in the document that I want is retrieved via a query string value. Below is my server side code:

  //set server control properties

  xmlDescription.DocumentSource= "../bin/works.xml";

  xmlDescription.TransformSource= "../bin/works.xslt";

  //create argument list and transform

  XsltArgumentList list = new XsltArgumentList();

  list.AddParam("index", "",Request.QueryString["works"].ToString ());

  xmlDescription.TransformArgumentList= list;

  xmlDescription.Visible= true;

  My revised xsl code is as follows:

  < xml version="1.0" encoding="UTF-8" >

  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:param name="index"></xsl:param>

  <xsl:template match="works">

  <xsl:for-each select="work/index[index == $index]">

  <table cellspacing="0" cellpadding="2" width="100%">

  <tr>

  <th>Title</th>

  </tr>

  <tr>

  <td>

  <value-of select="description" />

  </td>

  </tr>

  <tr>

  <td>

  <value-of select="size" />

  </td>

  </tr>

  <tr>

  <td>

  <b>Price: </b>

  <value-of select="price" />

  </td>

  </tr>

  </table>

  </xsl:for-each>

  </xsl:template>

  </xsl:stylesheet>

  The new error message that I am receiving is:

  The expression passed to this method should result in a NodeSet.

  Any ideas. I'm still using the same XML file for my data.

  
  

• Michael Lutz

  There are multiple problems with the logic in your XSL, but you can figure that out eventually once you get past the first hurdle of a proper xsl document. Here is the correct document that should fix the majority of your troubles. You did not use the xsl namespace in the stylesheet tag which seems to be causing your problem.

  < xml version="1.0" encoding="utf-8" >

  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:param name="index">1</xsl:param>

  <xsl:template match="/">

  <xsl:for-each select="works/work/index[. = $index]">

  <div><xsl:value-of select="title" /></div>

  </xsl:for-each>

  </xsl:template>

  </xsl:stylesheet>
  

  
  
• The wrong name space was used for XSL headaches...