Defining new field of array type (Reflection.Emit)

Defining new field of array type (Reflection.Emit)

• Witi

  So how can I instaniate the new array with specified length

  I didnt find in the FieldBuilder class an option to do this.

  
  
  

• Mostafa Omar

  So using the Activator.createInstance how would this look
  
  I have an interface, but I don`t know which implementation I am using at the moment.
  
  For example, I have the type theat implements Interface1:
  
  <code>
  
  Type type = getImplementedTypeFromSomeWhereElse();
  
  // I then have a list of type: IList<Interface1>
  IList<Interface1> list = getPopulatedListFromSomeWhereElse();
  
  // Then I need to create the array
  Interface1[] objects = Activator.CreateInstance(type.MakeArrayType());
  
  // How do I set the length
  
  // Copy list objects to the array
  for (int i = 0; i < list.Count; i++)
  {
  objects = list[ i ];
  }
  
  </code>
  
  Thanks,
  
  

• bodalal

  In this case you use Array.CreateInstance instead.

  Interface1[] objects = (Interface1[])Array.CreateInstance(type, arrayLength);

  
  
  

• LMcFarlin

  You generate code (in a constructor for example) that creates it using the newarr opcode.

  If you're not sure how it should look like, compile the corresponding C# code and look at it with Ildasm.

  class Test { Test[] t = new Test[2]; }

  
  
  

• Aleborg

  The length of an array is not a property of its type, it's a property of the instance. You set it when you instantiate the array, the field type is still myType[].

  
  
  
• Defining new field of array type (Reflection.Emit)