Software Development Network>> Visual Basic>> File Open Dialog
I am trying to code to get the File Open dialog.How do I do it
Can anyone post a sample code, please
Try this:
Thanks a ton for all your help.
I tried this one and was successful.
Using the CommonDialog Control I was able to bring up the Open Dialog.
CommonDialog1.ShowOpen
Dim dialog As New OpenFileDialog()
If dialog.ShowDialog() = Windows.Forms.DialogResult.OK Then
MessageBox.Show(dialog.FileName)
End If
I am sorry to have not mentioned this before.
I am using VB6.
Thanks for the Sample code!
However, I seem to be getting syntax error for :
Using dialog As New OpenFileDialog()End UsingEnd Using
Sorry, what version of Visual Basic are you using
That looks like VB6 code.
File Open Dialog
Aengus
Try this:
Using dialog As New OpenFileDialog()
If dialog.ShowDialog() = DialogResult.OK Then
MessageBox.Show(dialog.FileName)
End If
End Using
manhatma
Thanks a ton for all your help.
I tried this one and was successful.
Using the CommonDialog Control I was able to bring up the Open Dialog.
CommonDialog1.ShowOpen
Yogesh Roy MSFT
Try this:
Dim dialog As New OpenFileDialog()
If dialog.ShowDialog() = Windows.Forms.DialogResult.OK Then
MessageBox.Show(dialog.FileName)
End If
Marcus Ogden
I am sorry to have not mentioned this before.
I am using VB6.
StevenSw
Thanks for the Sample code!
However, I seem to be getting syntax error for :
Using dialog As New OpenFileDialog()End Using
End Using
José Nelson
Sorry, what version of Visual Basic are you using
That looks like VB6 code.