One app, multiple main()'s

One app, multiple main()'s

• Gohan222

  That still won't let me pick which main to run.
  
  thanks - dave
  
  

• Golf4Fun

  Hi;
  
  I'm not building, just running it. I don't want to recompile each time I need a different main in the exe. And that would never work when telling customers using it as they don't even have the compiler.
  
  thanks - dave
  
  
  

• Christatos

  Hi;
  
  What I want is a little different. I have the .exe and I want to run the .exe using a given main - like you can do with jar files under java. I don't want to require a recompile each time the main program is changed.
  
  thanks - dave
  
  

• Dreamtec

  Hi;
  
  This works, except I have a command line for some of these main programs. So for those I have to pass part of the command line through.
  
  Isn't there any way to start a program and tell it what main to use Java has had this from the begining so you would think .net would have it too.
  
  If not I guess I'll have to do as you showed - yuck.
  
  thanks - dave
  
  

• charlie_niner

  Refer my above post -
  
  

  If you are building from command line you can use /m[ain]:<class> option of vjc.exe. If you are building using VS, you can set the "Startup Object" property in the Project Properties->Application page. Thanks, Gautam

  
  

• Tan Silliksaar

  Hi David,
  As of now I don't know if this scenarios is supported in any .net language. I can also only think of the workaround suggested by Kazuya. I will get back you you by tommorow with details.
  
  Thanks.
  
  

• ashishth

  If you are building from command line you can use /m[ain]:<class> option of vjc.exe.
  
  If you are building using VS, you can set the "Startup Object" property in the Project Properties->Application page.
  
  Thanks,
  Gautam
  

• Yogesh Ranade

  Hi;
  
  I can't do that because I am running this from nant so I need to have a command line that sets it. like "java net.windward.xmlreport.RunReport" to run that main in a jar.
  
  thanks - dave
  
  

• David Teitlebaum MSFT

  Try refelction to do it like the following.
  
  Class.forName(className).getMethod("main", new Class[] { String[].class }).invoke(null, new Object[] { stringArray });
  
  Kazuya Ujihara
  

• Val Maltsev

  Add the following class and set it startup object.
  
  class Program
  {
   public static void main(String[] args) throws Throwable
   {
    if (args.length < 1)
    {
     System.err.println("Missing arguments.");
     System.exit(1);
    }
    String className = args[0];
    String[] stringArray = new String[args.length-1];
    System.arraycopy(args, 1, stringArray, 0, args.length - 1);
    Object ret;
    try
    {
     ret = Class.forName(className).getMethod("main", new Class[] { String[].class }).invoke(null, new Object[] { stringArray });
    }
    catch (java.lang.reflect.InvocationTargetException ite)
    {
     throw(ite.getTargetException());
    }
    if (ret == null || !(ret instanceof Integer))
     System.exit(0);
    System.exit(((Integer)ret).intValue());
   }
  }
  
  You can handle '-D' and '-cp' option of JavaVM using this approach.
  
  

• ManchesterMike

  Set 'java' to your assembly name.
  Of course, have known it's a crazy ideal.

  
  
• One app, multiple main()'s