java.lang.Math.hypot J# equivalent?

I'm a total newbie to J#, I'm a C# and VB.NET programmer. I know a bit about Java, but not at a professional level, and I need to convert a Java program to J#. The part that I'm stuck on is I need to find a J# equivalent method of:

java.lang.Math.hypot

Any ideas Also, I need to have the same exact results, not a result that is "close enough and will suffice."

Thanks:)

Answer this question

java.lang.Math.hypot J# equivalent?

QueenAji
java.lang.Math.hypot(x, y) is identical with System.Math.Sqrt(x * x + y * y).

CLR handles Infinity and NaN correctly.
Rumi
Hi,

We are not supporting this hypot function in our libraries.I have a snippet of code to solve your problem

public static double hypot(double a, double b)

{

a = Math.abs(a);

b = Math.abs(b);

if (a < b)

{

double temp = a;

a = b;

b = temp;

}

if (a == 0.0)

return 0.0;

else

{

double ba = b / a;

return a * Math.sqrt(1.0 + ba * ba);

}

}

I think this will solve your problem.

regards,

Thilak
Alexander Dragon
thanks, that worked like a charm:)
java.lang.Math.hypot J# equivalent?

Answer this question

java.lang.Math.hypot J# equivalent?

Hot Topic

Visual J#

java.lang.Math.hypot J# equivalent?

java.lang.Math.hypot J# equivalent?

QueenAji

Rumi

Alexander Dragon