Reading A File...

Reading A File...

• Robert Beaubien

  Figured it out. Thanks for help, guys.
  

• Aaron Hallberg - MSFT

  In Java, I used something called a 'StringTokenizer'.  Is there a substitute for this within C#   The file that i am reading contains the following: "one", "2", "three".  I need to get all three values out of line.  I am using ReadLine to take the line out of the file, but I need to seperate all 3 values.
  

• Mark Ainsworth

  Create an instance of the Open File Dialog and fill the properties. Then show the Dialog.

  OpenFileDialog openFiles = new OpenFileDialog ( );

  openFiles.InitialDirectory = "C:\Temp\";
  openFiles.Filter = "Text files (*.txt)|*.txt";
  openSsnKount.FilterIndex = 1;
  openSsnKount.RestoreDirectory = false;

  if ( openSsnKount.ShowDialog ( ) == DialogResult.Cancel )
  {
  openSsnKount.Dispose ( );
  }

  That's about it except what you want to do with the selected file.

  
  
  

• Brian Layden

  The String.Split is working great. However, lets say I have the following string: "one", "two", "three". How could I store each of these values into a seperate variable

  I currently have the following code:

  string line = sr.ReadLine();

  char[] seps = new char[]{','};

  foreach (string ss in line.Split(seps))

  {

  how would i make it so:

  string 1 = one
  string 2 = two
  string 3 = three

  }

  Thanks Again,

  
  

• MBowen

  I think you are looking for String.Split.
  
  

• Andrew O.

   

  Hi,

  
  Just do the following steps…

   

  Put a text box on the form (optional:set its multi line property to true and dock fill).

   

  Write following code in Open menu

   

  OpenFileDialog opd = new OpenFileDialog();             if (DialogResult.OK==(opd.ShowDialog()))                 textBox1.Text = ReadFile(opd.FileName);

   

   

  Write following code in Save menu

   

  SaveFileDialog sfd = new SaveFileDialog();             if (DialogResult.OK==(sfd.ShowDialog()))                 SaveFile(sfd.FileName);

   

  Write following functions on the form to open and read file and return a string

   

  string ReadFile(string path)         {                         try             {                 StreamReader sr = new StreamReader(path);                 string data=sr.ReadToEnd();                 sr.Close();                 return data;                             }             catch (Exception exception)             {                 //handle error                 return "";                            }

   

   

  Write following function on the form to read text from text box and save to file

   

  void SaveFile(string path)         {                         try             {                   StreamWriter sw = new StreamWriter(path);                                 sw.Write(textBox1.Text);                 sw.Flush();                 }               catch (Exception ex)             {                 //error handling             }                             }

   

  Hope this help.

  
  
  
• Reading A File...