Access a bit in a Byte, Help!

Access a bit in a Byte, Help!

• MyNameisMud

  The result of a bitwise & is an int or a long, even when operating on a byte. Either cast the result, or more simply, use &=:
  
  

  receive_buf_array[2] &= 3;

  
  
  Jon
  
  
  
  

• ndhuy

  I am trying to mask a byte value (receive_buff[2]) with a mask value of 3 (bit value 0000 0011) however, I am getting an error of "Cannot implicitly convert type 'int' to 'byte'".
  
  receive_buf_array[] and receive_buff[] are arrays of bytes.
  
  Here's my statement:
  
  

  receive_buf_array [2]=(receive_buf[2]&3);

  What am I doing wrong
  
  

• ROBSR

  John,
  
  Thanks for your reply. I used your other suggestion in the other thread.
  

• jdegaetani

  To see if a bit is set in a byte you do a bitwise "and" operation. That is the "&" operator in C#
  
  You use a mask to check what is set
  
  Bit#       Decimal value
  87654321
  
  00000001 = 1
  00000010 = 2
  00000100 = 4
  00001000 = 8
  00010000 = 16
  00100000 = 32
  01000000 = 64
  10000000 = 128
  
  So to check if bit 2 is set in a byte we and it with the mask of decimal value of 2 and then see if it is equal to the mask
  
  

  Byte byData = ...;     Byte byMask = 2;     if ((byData & byMask) == byMask)     {        MessageBox.Show("Bit 2 is set!");     }

  
  
  
  
• Access a bit in a Byte, Help!