hi,
i'm building a small game like puzzle so i need to swap an array items in different order each time i run my program, every time i use random it works and make the array order diferent but the problem is every time it give the same result as if i used fixed number here its example of my code in
class Program { static int[] Numbers = { 0, 1, 2, 3, 4, 5, 6, 7, 8 }; static void Main(string[] args) { Random rnd = new Random(0); int i, j, tmp; for (i = 0; i < Numbers.Length; i++) { // the problem in this part j = rnd.Next(0,8); tmp = Numbers[ i ]; Numbers[ i ] = Numbers[ j ]; Numbers[ j ] = tmp; } //show the result for ( i = 0; i < Numbers.Length; i++) { Console.WriteLine("item[{0}] = '{1}'",i,Numbers[ i ]); } } } |
the result will be the same every time you run this, even though it use random even if i make it other method and called it 2 times it change the order correctly first result not like second result, but if i run my progam again and did 2 trials (first time > first trial exactly the same like second time > first trial , and the second trial is the same too)
i want to do this in different way every time i run the program or the random generator
is there anyway to do that
thx in advance
Random give the same value
peter_heard01
The argument you are passing to Random constructor is seed. IOW if you pass same value you will get same sequence.
If you want more random behaviour then you shouldn't pass any value, like:
Random rnd = new Random();
or you should pass a random value you get from somewhere.